**Test 1:**

Reverse the number . Mulitply each digit of this reversed number by the digits 1(=1%7),3(=10%7),2(=100%7),6(=1000%7),4(=10000%7),5(=100000%7) consequtively till all digits are covered. Sum the products. If this value is divisible by 7 then the original number is too.

Actually these numbers are the cyclic remainders of division by 7.

**Test 2:**

Take the last digit of the number and subtract it from the number formed by the remaining digits.If this value is divisible by 7 then the original number is too. We can do it recursively to reduce the number .

Hope that helps.

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